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Question for Michael Dalton

 Posted by Sum Yung Foo on 16 February 2003, at 1:57 p.m.
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On page 79 of your reference, you give a formula for the "percentage of the SD" that says
 

% SD = 1.1

 
---------- * 100
 
Sqrroot(N)
 

So does that mean that for 100 hands one standard deviation equals

 

.1111 * 100 = 11%?

 

In other words, do we multiply 11% times the total action (N * flat bet size) to get one SD? Thanks.


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